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3 Phase Power Calculator HP To Amps

3 Phase Power Formula:

\[ I = \frac{HP \times 746}{V \times \sqrt{3} \times PF \times Eff} \]

HP
volts
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dimensionless

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1. What is the 3 Phase Power Formula?

The 3 phase power formula calculates electrical current (amps) from mechanical power (horsepower) in a three-phase AC system. It accounts for voltage, power factor, and efficiency to provide accurate current measurements for motor sizing and electrical system design.

2. How Does the Calculator Work?

The calculator uses the 3 phase power formula:

\[ I = \frac{HP \times 746}{V \times \sqrt{3} \times PF \times Eff} \]

Where:

Explanation: The formula converts mechanical power to electrical power, then calculates the current required based on system voltage and power characteristics.

3. Importance of Current Calculation

Details: Accurate current calculation is essential for proper wire sizing, circuit breaker selection, motor protection, and ensuring electrical system safety and efficiency in industrial applications.

4. Using the Calculator

Tips: Enter horsepower, system voltage, power factor (typically 0.8-0.95 for motors), and efficiency (typically 0.8-0.95). All values must be positive numbers within their valid ranges.

5. Frequently Asked Questions (FAQ)

Q1: Why is the conversion factor 746?
A: 746 watts equals 1 horsepower, which is the standard conversion between mechanical and electrical power units.

Q2: What is power factor and why is it important?
A: Power factor represents the ratio of real power to apparent power. Lower power factors require higher current for the same real power, increasing system losses.

Q3: When should this formula be used?
A: For three-phase AC motor applications, industrial equipment sizing, and electrical system design where horsepower ratings are known.

Q4: Are there limitations to this calculation?
A: This assumes balanced three-phase systems and may not account for starting currents, voltage drops, or non-linear loads.

Q5: How does efficiency affect the calculation?
A: Lower efficiency means more electrical input power is required to produce the same mechanical output, resulting in higher current draw.

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