Hp To Fla Calculator

FLA Formula:

\[ FLA = \frac{HP \times 746}{V \times \sqrt{3} \times PF \times Eff} \]

Horsepower (HP):

Voltage (V):

Power Factor (PF):

(dimensionless)

Efficiency (Eff):

(dimensionless)

Full Load Amps (FLA):

Unit Converter ▲

Unit Converter ▼

From:	To:

1. What is the FLA Formula?

The FLA (Full Load Amps) formula calculates the current drawn by an electric motor under full load conditions from horsepower, voltage, power factor, and efficiency. It is essential for proper electrical system design and motor protection.

2. How Does the Calculator Work?

The calculator uses the FLA formula:

\[ FLA = \frac{HP \times 746}{V \times \sqrt{3} \times PF \times Eff} \]

Where:

\( HP \) — Horsepower
\( V \) — Voltage (volts)
\( PF \) — Power factor (dimensionless)
\( Eff \) — Efficiency (dimensionless)
\( \sqrt{3} \) — 1.732 (dimensionless, for three-phase systems)
746 — Conversion factor from HP to watts

Explanation: The formula converts mechanical power (HP) to electrical power (watts), then calculates current based on voltage, power factor, and efficiency for three-phase AC systems.

3. Importance of FLA Calculation

Details: Accurate FLA calculation is crucial for proper circuit breaker sizing, wire selection, motor protection device setting, and ensuring electrical system safety and efficiency.

4. Using the Calculator

Tips: Enter horsepower, voltage, power factor (typically 0.8-0.95), and efficiency (typically 0.7-0.95). All values must be positive numbers within their respective valid ranges.

5. Frequently Asked Questions (FAQ)

Q1: What is the significance of the 746 factor?
A: 746 watts equals 1 horsepower, so this factor converts mechanical power to electrical power.

Q2: Is this formula for single-phase or three-phase systems?
A: This specific formula with √3 is for three-phase systems. For single-phase systems, the formula is different (FLA = (HP × 746) / (V × PF × Eff)).

Q3: What are typical power factor values?
A: Power factor typically ranges from 0.8 to 0.95 for most industrial motors at full load, but can be lower at partial loads.

Q4: Why is efficiency included in the calculation?
A: Efficiency accounts for power losses in the motor, ensuring the calculation reflects the actual electrical input power required.

Q5: How accurate is this calculation for motor sizing?
A: This provides a good estimate, but always refer to the motor nameplate for exact FLA values and consult electrical codes for proper sizing.